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barxatty [35]
3 years ago
8

Plzzz tell ans but not for points​ okkkkay if u ans for points i will report

Mathematics
2 answers:
PolarNik [594]3 years ago
7 0

Answer:

[i] In ΔABC and ΔADC,

  • ∠BAC = ∠ADC = 90°
  • ∠ACB = ∠ACD (common)

So, ΔABC ~ ΔDAC by AA similarity.

[ii] We know that, if two triangles are similar then their ratio of corresponding sides are equal

  • AC/DC = BC/AC
  • AC² = BC × DC (croos multiplication)
VikaD [51]3 years ago
7 0

Answer:

<u>Given</u>

  • ΔABC with ∠A = 90°
  • ΔADC with ∠D = 90°
  • The two triangles share same angle ∠C

<u>With two same angles the triangles are similar according to AA similarity postulate:</u>

  • ΔABC ~ ΔDAC

<u>As we know if triangles are similar then their corresponding sides have same ratio:</u>

  • AC/CD = BC/AC ⇒ AC*AC = BC*CD ⇒ AC² = BC*CD

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