At 6am the temperature was -5. In the afternoon it was 10 C. What was the change of temperature during the day?
2 answers:
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Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:
*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
Answer:
a)
b)
c)
d)
e)
Step-by-step explanation:
a) 8 = 2 x 2 x 2
b) 32 = 2 x 2 x 2 x 2 x 2
c) 256 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2
d) 5 x 2^3 / 64 = 5 x 8 / 64
= 40/64
= 5/8
=
e) 16 - (-2)^3 = 16 - (-8)
= 16 + 8
=