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3 years ago

What is the median and mean of: 12,5,10,11,8,15,14

Mathematics

2 answers:

alukav5142 [94]3 years ago

4 0

The mean is: 10.714

The median is 11

Eddi Din [679]3 years ago

3 0

Median= 11
Mean= 10.7

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Anton [14]

Answer:

Assuming you are asked for the equation of the graph, the answer would be y=|x+2|-1.

Step-by-step explanation:

The parent function for the "V-shape" is y=|x|. This particular function is translated to the left two units and down one. This is shown by adding two to x within the absolute value and subtracting one from the absolute value of x+2, leaving you with y=|x+2|-1. If you plug this equation into desmos online graphing calculator, you will see that the graph is identical to the one given.

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2 years ago

A line passes through the points A(n,4) and B(6,8) and is parallel to y=2x-5. What is the value of n?

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(4,6),(5,3),(7,2),(9,3)

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3 years ago

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What is the rate of change <br> x y<br> -2 -6<br> -1 -3<br> 0 0

Natalka [10]

So you subtract their integers by starting from the bottom then coming up to the top. And you just put the numbers in your calculator. Once you’ve got your answer for X and Y, you multiply them both. Which will give you -9/3. Next you divide -9 by 3 and 3 divided by 3. Which will give you -3/1 and just rewrite it as -3. I don’t know if this helps but I hope it does :).

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3 years ago

Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180

torisob [31]

I got

$- \frac{6 3}{65}$

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

$\cos(a - b) = \cos(a) \cos(b) + \sin(a) \sin(b)$

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

${12}^{2} + {y}^{2} = {13}^{2}$

$144 + {y}^{2} = 169$

$25 = {y}^{2}$

$y = 5$

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

$( - 3) {}^{2} + {x}^{2} = {5}^{2}$