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asambeis [7]
3 years ago
13

In 2.5 hours, Mr. Castelli drives a distance of 125 miles. He wants to know his average driving speed in meters per minute. Comp

lete the table to find Mr. Castelli's average driving speed in meters per minute by using the units as a guide.
Mathematics
1 answer:
julia-pushkina [17]3 years ago
3 0
<span>The correct answer is 1.35km/min=1350 meters/min</span>
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Felipe, Pedro y Miguel son fanáticos del cine. Felipe asiste cada 3 días; Pedro cada 6 días y Miguel cada 5 días. Los tres van j
lilavasa [31]

Answer:

Opción C, 30 días.

Step-by-step explanation:

Sabemos que:

Felipe asiste al cine cada 3 días

Miguel asiste cada 5 días.

Pedro asiste cada 6 días.

Los tres van juntos un día,  ¿dentro de cuántos días irán otra vez juntos?

Los 3 volverán a ir juntos luego de N días, tal que N es el menor múltiplo común de 3, 5 y 6.

Como 6 es múltiplo de 3, podemos ignorar al 3, y solo considerar al menor múltiplo en común de 5 y 6.

Además, como podemos reescribir estos números como un producto de números primos, así obtenemos:

6 = 2*3

5 = 5*1

Estos números no comparten factores entre ellos, por lo que el menor múltiplo entre 5 y 6 es simplemente 5*6 = 30

Entonces podemos concluir que N = 30

Felipe, Pedro y Miguel irán juntos al cine nuevamente dentro de 30 días.

La opción correcta es C.

5 0
3 years ago
Solve the equation 36w = 16w + 24
Umnica [9.8K]
=24/20 thus the answer is 1.2
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3 years ago
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Could u solve this pls?
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The answer is 20. Hope it helps.
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3 years ago
Suppose that you take a sample of 250 adults. If the population proportion of adults who watch news videos is 0.58​, what is the
aliina [53]

Answer:

0.36% probability that fewer than half in your sample will watch news​ videos

Step-by-step explanation:

To solve this question, i am going to use the binomial approximation to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 250, p = 0.58

So

\mu = E(X) = 250*0.58 = 145

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{250*0.58*0.42} = 7.80

If the population proportion of adults who watch news videos is 0.58​, what is the probability that fewer than half in your sample will watch news​ videos

Half: 0.5*250 = 125

Less than half is 124 or less

So this is the pvalue of Z when X = 124

Z = \frac{X - \mu}{\sigma}

Z = \frac{124 - 145}{7.8}

Z = -2.69

Z = -2.69 has a pvalue of 0.0036

0.36% probability that fewer than half in your sample will watch news​ videos

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3 years ago
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