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3 years ago

8

While shopping, you see a jacket marked down 20%. If the original price of the jacket is $175, what is the sale price of the jac

ket

2 answers:

myrzilka [38]3 years ago

7 0

Answer: The required sale price of the jacket is $140.

Step-by-step explanation: Given that while shopping, we see a jacket marked down 20% and the original price of the jacket is $175.

We are to find the sale price of the jacket.

Since we are getting a discount of 20%, so the sale price will be original price minus the discount price.

The discount price is given by

$D_p=20\%\times 175=\dfrac{20}{100}\times175=\dfrac{175}{5}=35.$

Therefore, the sale price of the jacket is given by

$S_p=175-D_p=175-35=140.$

Thus, the required sale price of the jacket is $140.

kolezko [41]3 years ago

3 0

To find the answer multiply $175 by 0.2. This will give you $35. Now, you have to subtract $175 by $35. Therefore, the sale price will be $140.

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2 years ago

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3 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

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Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

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$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

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$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

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3 years ago