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3 years ago

The shape above is made of cubes. How many total cubes make up the shape?

Mathematics

2 answers:

melamori03 [73]3 years ago

7 0

Answer:

Step-by-step explanation:

there are 6 blue cubes facing you

there are 3 rows of 6 cubes

3 x 6 = 18

Marat540 [252]3 years ago

3 0

Answer:

A. 18

Step-by-step explanation:

If we look down the right side of the shape, each row is made up of 6 cubes. there are 3 rows in the shape.

3*6 = 18

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3^4 + 4 . 5 = _ (input whole numbers only.)

anygoal [31]

3^4=81
4*5=20
81+20=101
Hope this helped

6 0

3 years ago

If g(x)=6/(x-3) find g(5)

alexandr1967 [171]

Answer:

the answer is 3

Step-by-step explanation:

function notation is the way a function is written.

6 0

2 years ago

Help please questions are in the picture

vredina [299]

Question number 1:

Answer:

Answer B

Step-by-step explanation:

Add the prices

$143.99 + $82.40 = $226.39

Multiply by 6

$226.39 · 6 = $1358.34

Answer B, 1358.34

7 0

2 years ago

Read 2 more answers

Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p

zubka84 [21]

Answer: The required answers are

(a) 0.25, (b) 0.62, (c) 6.

Step-by-step explanation: Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

$P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.$

(a) The probability of getting 5 heads is given by

$P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.$

(b) The probability of getting 5 or more than 5 heads is

$P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.$

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

$P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.$

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0

3 years ago

15 - 8x2 + 6x - 4x2 +11

Oksanka [162]

Answer:

-2 • (6x2 - 3x - 13)

Step-by-step explanation:

8 0

2 years ago