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just olya [345]
3 years ago
13

The height of the rectangular prism measures 64 cm. If the height is increased by 1.5​ cm, by how much will the surface area of

the box​ increase?

Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

Increase in surface area =  126 cm²

Step-by-step explanation:

Surface area of the rectangular prism has the dimensions as

Length = 42 cm

Width = 35 cm

Height = 64 cm

Total surface area of the rectangular prism = 2(lb + bh + hl)

Here, l = Length of the box

b = Width of rectangular box

h = height

Total surface area = 2(42×35 + 35×64 + 64×42)

= 2(1470 + 2240 + 2688)

= 12796 cm²

If height is increased by by 1.5 cm, new height of the box = 64 + 1.5 = 65.5 cm

Surface area of the box = 2(42×35 + 35×65.5 + 65.5×42)

= 2(1470 + 2240 + 2751)

= 12922 cm²

Increase in surface area = 12922 - 12796

                                          = 126 cm²

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Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

\sf A=lw

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

\sf A=(56)(27)

\sf A=1512cm^2

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

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Calculate the area:

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\sf 739.8\times 2=1479.6\? cm^2

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Now find the area:

\sf A=\dfrac{1}{2}bh

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