Answer:
Lily is correct.
An example of a working solution to this problem is: 6/3 + 1/2 + 4/8.
Step-by-step explanation:
An integer is essentially a whole number(is not a part), but with negative numbers as well. Given whole numbers from 1 to 9, This can be an integer because an integer <u>includes</u> whole numbers.
The value of y is 5
<h3>How to determine the value </h3>
From the given line, it can be concluded that:
The segment RT is divided into RS and ST
But we have the following parameters
The length of the sides are:
Since RT is RS added to ST:
We have;
RT = RS + ST
substitute the values
43 = 4y + 4 + 3y + 4
collect like terms
43 = 4y + 3y + 4 + 4
Add like terms
43 = 7y + 8
43 = 7y + 8
Make '7y' subject of formula
7y = 43 - 8
7y = 35
Make 'y' the subject of formula
y = 35/ 7
y = 5
Thus, the value of y is 5
Learn more about segments here:
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We start with the more complicated side which is the left side, and show that, on using some trigonometric identities, we will get the term on the right side .
Using Quotient identity for tangent function, we will get
Taking out sine function from the numerator
Cancelling the common term of numerator and denominator
You multiply the constants 3 * 2 = 6
Add you add the exponents 6 + 1/2 = 13/2
So the answer is 6x^(13/2)
(D)
Take the unknown number as 'y'.
=》33% = 33/100
=》1.45 = 145/100
33/100 × y = 1.45
33/100 × y = 145/100
33y = 145/100 × 100/1
33y = 145
y = 145/33
y = 4.39
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RainbowSalt2222 ☔
