Evaluate the following expression. 1/5^-2 Evaluate 6^-3

Mathematics

2 answers:

Marizza181 [45]3 years ago

7 0

1/5^-2 = 5^2 so this equals

= 25

melisa1 [442]3 years ago

6 0

$( \frac{1}{5}) ^{-2} = ( \frac{5}{1} )^{2} = 5^{2} = 25 \\ \\ 6^{-3} = ( \frac{6}{1} )^{-3} = ( \frac{1}{6} )^{3} = \frac{ 1^{3} }{ 6^{3} } = \frac{1}{216}$

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A normal distribution has a mean of 137 and a standard deviation of 7. Find the z-score for a data value of 121. Incorrect Round

Neko [114]

Answer:

The z-score for a data value of 121 is -2.29.

Step-by-step explanation:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 137, \sigma = 7$