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4 years ago

Evaluate the following expression. 1/5^-2 Evaluate 6^-3

Mathematics

2 answers:

Marizza181 [45]4 years ago

7 0

1/5^-2 = 5^2 so this equals

= 25

melisa1 [442]4 years ago

6 0

$( \frac{1}{5}) ^{-2} = ( \frac{5}{1} )^{2} = 5^{2} = 25 \\ \\ 6^{-3} = ( \frac{6}{1} )^{-3} = ( \frac{1}{6} )^{3} = \frac{ 1^{3} }{ 6^{3} } = \frac{1}{216}$

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Vesna [10]

Answer:

The relationship between the graphs of the two functions is "They are reflections of each other across the y-axis" ⇒ B

Step-by-step explanation:

If the function f(x) reflected across the x-axis, then the new function g(x) = - f(x), which means the signs of the y-coordinates of the points on f(x) are opposite in g(x)

If the function f(x) reflected across the y-axis, then the new function g(x) = f(-x), which means the signs of the x-coordinates of the points on f(x) are opposite in g(x)

∵ The points on f(x) are (-2, -31), (-1, 0), (1, 2), (2, 33)

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∴ The relationship between the graphs of the two functions is

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3 years ago

Find the vertex of the parabola whose equation is y = x2 + 8x + 12.

lara31 [8.8K]

We will transform the equation to the vertex form:
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3 years ago

Read 2 more answers

Tammy and Leslie are best friends, and

photoshop1234 [79]

Tammy was taller at age 9, as she was 3.68 inches taller than Leslie.

<h3><u>Equations</u> </h3>

Given that Tammy can model her height using the equation, y = 2.2x + 35.5, where y represents her height at x years of age, while Leslie measured 50 inches at age 9, to determine who was taller at that age one must perform the following calculation:

Leslie = 50
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Therefore, Tammy was taller at age 9, as she was 3.68 inches taller than Leslie.

Learn more about equations in brainly.com/question/10413253

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3 years ago

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beks73 [17]

Answer:

Step-by-step explanation:

5x8=40+4=44

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3 years ago

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