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aniked [119]
3 years ago
13

The product of two numbers is 192. what is the minimum value of the sum of the first value plus twice the second value

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0
Let x and y be the two positive numbers. -  Their product is 192: x *  y  =  192   equation 1

-  the sum of the first plus twice the second is a minimum:  x + 2y

<span>From the first equation, y =  192 / x. 
Substitute that into the second equation:
</span>
 x + 2y = x + 2(<span>192/x ) = x + 384/x

</span>f(x) is minimum when f'(x) = 0 and f"(x) > 0 

f(x)= <span>x + 384/x
</span>
f(x) = 1-384/x^2 

<span>1-384  / x^2 =  0 

x^2-384 = 0 

x^ 2= 354
 x = radical  354    = 18.8  here i'm confused why the number is decimal
???/ 
</span>

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Using the difference of two squares:

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For the expression x^2 + 9

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Learn more on factorization here: brainly.com/question/20293447

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erik [133]
This may not be very pretty.
(2x + 5) * (2x + 5) expanded is (use foil)
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I = 2x + 5 = 10x
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(x + 3)(x + 3) = x^2 + 6x + 9 by the same method

 (2x + 7)(2x + 7) = 4x^2 + 28x + 49 Same method.

4x^2 + 20x + 25 + x^2 + 6x + 9 = 4x^2 + 28x + 49
5x^2 + 26x + 34 = 4x^2 + 28x + 49 Collect everything on the left.
x^2 - 2x - 15 = 0
(x - 5)(x + 3) = 0
x + 3 will have no meaning.
x - 5 = 0
x = 5

2x + 5 = 2*5 + 5 = 15
x + 3 = 5 + 3 = 8
2x+ 7 = 2*5 +7 = 17

Check
15^2 + 8^2 = 17^2
225 + 64 = ? 289
289 = 289

a = 15 <<<<< answer
b = 8 <<<<< answer
c = 17 <<<<< answer
 


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