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3 years ago

The product of two numbers is 192. what is the minimum value of the sum of the first value plus twice the second value

1 answer:

4 0

Let x and y be the two positive numbers. - Their product is 192: x * y = 192 equation 1

- the sum of the first plus twice the second is a minimum: x + 2y

From the first equation, y = 192 / x.
Substitute that into the second equation:

x + 2y = x + 2(192/x ) = x + 384/x

f(x) is minimum when f'(x) = 0 and f"(x) > 0

f(x)= x + 384/x

f(x) = 1-384/x^2

1-384 / x^2 = 0

x^2-384 = 0

x^ 2= 354
x = radical 354 = 18.8 here i'm confused why the number is decimal
???/

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xz_007 [3.2K]

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3 years ago

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Make a Matlab script to make row 2 of matrix A equal to first row of A multiplied by the negative of the first element of row 2

stira [4]

Answer:

$X=\begin{Bmatrix}2& 1 &10 \\-3 & 5 & 4\end{Bmatrix}$

Step-by-step explanation:

From the question we are told that

Matrix is given as $A=\begin{Bmatrix}2 & -1 & 10\\-3 & 8 & 4\end{Bmatrix}$

Generally let the change in matrix be given as X

$X_1_2 = 2*(-(-1)) + - 1 = 1X_2_2 = -3 * (-(-1))+ 8 = 5$

Matlab output

$A=[2 -1 10;-3 8 4]\\a=(A(1,1)*-A(1,2))+A(1,2)\\b=(A(2,1)*-A(1,2))+A(2,2)\\X=[A(1,1) a A(1,3); A(2,1) b A(2,3)]\\$

Generally the matrix that makes row 2 of matrix A equal to first row of A multiplied by the negative of the first element of row 2 plus the original row is

$X=\begin{Bmatrix}2& 1 &10 \\-3 & 5 & 4\end{Bmatrix}$

6 0

3 years ago

Pls do all of them... :) (it’s so rude and annoying sometimes to bcuz I help ppl when they don’t help me for once...pls help me

Genrish500 [490]

Answer:

1A: 12

Step-by-step explanation:

2A: 16

3A: 21.333

4A: 13

5A: 14

1B: 15

2B: 12

3B:29

4B: 11

5B: 24

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3 years ago

College LEVEL can you help me? :S

Yanka [14]

Although the formula looks involved, the key here is looking to see where the information goes.

We are given all the pieces but need to convert mph to ft/s to use the formula. Let's do it with 1 mph so that we have a ratio to use. We and solve a unit conversion problem.

$\frac{1mile}{hour} * \frac{hour}{60 minutes} * \frac{minute}{60 seconds} * \frac{5280 feet}{mile} = \frac{5280}{60*60} = \frac{5280}{3600} = 1.46666$

That ratio tells us that 1 mph is 1.466666 ft/s. Now we solve two proportions.

1 mph / 1.466666 feet per second = 60 mph / x feet per second.

1x = (60)(1.466666)

So x = 88 feet per second.

Next, We repeat for 24 mph.

1 mph / 1.46666 feet per second = 24 mph / x feet per second.

1x = (1.4666666)(24)

x = 35.2 feet per second

Now we have the found appropriate V₁ and V₂. V₁ > V₂, so V₁ is 88 ft/s and V₂ is 35.2 ft/s. The problem tells us θ = 2.3 degrees, K₁ = .4 and K₂ = .06. The rest of the problem is calculator work. Start by substituting our degree measure of 2.3 degrees and the given values in the problem for V₁, V₂, K₁, and K₂

$D = \frac{1.05[(88)^{2}-(35.2)^{2}]}{64.4(.4+.06 + (sin 2.3))}$