The ratios are both identical
sin x = perpendicular/hypotenuse = 3/5
cosy = base/hypotenuse = 3/5
Answer:
Step-by-step explanation:
A matched pair t test is one in which the set of data is divided into two sets of data and the test is done to test the difference between the pairs. Sometimes this is called paired t test.\
This is done normally where one group of sample or population can be paired with other group of sample /population.
Hence
A .Measurements of annual income for each twin for 100 randomly selected pairs of twins -- True
B. Measurements of annual income for both individuals in pairs formed by matching 100 people from State A and 100 people from State B based on level of education -- True
C. Measurements of annual income for both individuals in pairs formed by assigning 100 people to pairs at random -- True
D. Measurements of annual income recorded for both spouses of 100 randomly selected married couples --False here we cannot say paired as these people are not grouped under the same conditions.
The answer is b. There is a proof, but it is easily got by proving the other cases wrong.
Answer:
y = 9
<em><u>plz</u></em><em><u> </u></em><em><u>mark</u></em><em><u> my</u></em><em><u> answer</u></em><em><u> as</u></em><em><u> brainlist</u></em><em><u> plzzzz</u></em><em><u> vote</u></em><em><u> me</u></em><em><u> also</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer: Hello!
Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)
We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.
The total number of permutations is the product of the number of options that you have for each letter, this is:
17*16*15*14*....*3*2*1 = 17! = 3.6e+14
(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is
30! = 2.65e+32
(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.
then P = 47! = 2.59e+59
(d) DERMATOGLYPHICS: here are 18 letters, then:
p = 18! = 6.4e+15
