The answer is 30 because you put 21/x= 70/100
you cross multiply 100 and 21 you get 2100 and you divide it by 70 you should get 30 cause you take out one 0 from both numbers and end up with 210 divided by 7 then you get 30
'll use the binomial approach. We need to calculate the probabilities that 9, 10 or 11
<span>people have brown eyes. The probability that any one person has brown eyes is 0.8, </span>
<span>so the probability that they don't is 1 - 0.8 = 0.2. So the appropriate binomial terms are </span>
<span>(11 C 9)(0.8)^9*(0.2)^2 + (11 C 10)(0.8)^10*(0.2)^1 + (11 C 11)(0.8)^11*(0.2)^0 = </span>
<span>0.2953 + 0.2362 + 0.0859 = 0.6174, or about 61.7 %. Since this is over 50%, it </span>
<span>is more likely than not that 9 of 11 randomly chosen people have brown eyes, at </span>
<span>least in this region. </span>
<span>Note that (n C r) = n!/((n-r)!*r!). So (11 C 9) = 55, (11 C 10) = 11 and (11 C 0) = 1.</span>
Answer:
x = -5/2
Step-by-step explanation:
Answer:
1/18
3/2
Step-by-step explanation:
18 = 18/1 if the reciprocal means to flip the denominator and the numerator then just witched them so it would be 1/18
2/3 would be 3/2
Answer:
your answer is going to be B: Obtuse
