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Luda [366]
4 years ago
15

roland sold 26 candy bars during the first week. the number of candy bars he sold during the second week was 4 less than 2 times

the number of candy bars he sold during the first week. the number of candy bars he sold during the third week was 6 more than 1 1/2 times the number of candy bars he sold during the second week. what was the total number of candy bars roland sold during the three weeks?

Mathematics
2 answers:
iVinArrow [24]4 years ago
6 0
The total number of candy bars he sold was 152 candy bars
STALIN [3.7K]4 years ago
5 0
****hope this helps****

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Step2247 [10]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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20.   The sum of two consecutive even integers is 158. Find the least of the two integers. 
Mumz [18]

Answer:

78

Step-by-step explanation:

The tricky part of this is figuring out how to assign the unknowns.  We are told that we are working with two consecutive even integers.  Consecutive means "next to" or "in order" and sum means to add.  If we use 2 and 4 as examples of our 2 consecutive even integers and assign x to 2, then in order to get from 2 to 4 we have to add 2.  So the lesser of the 2 integers is x, and the next one in order will be x + 2.  (2 and 4 are just used as examples; they mean nothing to the solving of this particular problem.  You could pick any 2 even consecutive integers and find the same rule applies.  All we are doing here with the example numbers is finding a rule for our integers.)  Now we have the 2 expressions for the integers, we will add them together and set the sum equal to 158:

x + (x + 2) = 158

The parenthesis are unnecessary since we are adding, so when we combine like terms we get

2x + 2 = 158 and

2x = 156 and

x = 78

That means that the lesser of the 2 integers in 78, and the next one in order would be 80, and 78 + 80 = 158

6 0
3 years ago
Read 2 more answers
2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
The segments shown below could form a triangle. True B. False​
Vesna [10]
True

It won’t be a Prefect Triangle but it still is one
(sorry my drawing is bad)

3 0
3 years ago
Given: triangle ABC,
Andrei [34K]

The value of AD in triangle ABC is approximately 9 cm.

BC = 6cm

Using trigonometric ratio for triangle CBD

sin 60° = opposite / hypotenuse

0.86602540378  =  DC / 6

cross multiply

DC = 6 × 0.86602540378

DC = 5.19615242271

DC = 5.20 cm

Let's find side AD as follows:

tan 60° = AD / adjacent

AD = 5.20 × tan 60°

AD = 9.00666419936

AD ≈ 9 cm

learn more: brainly.com/question/10929357?referrer=searchResults

7 0
3 years ago
Read 2 more answers
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