It can go to 3.5/9 but thats as low as it can go
Answer:
0.375 feet-lb
Step-by-step explanation:
We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.
We can represent our given information as:
We will use Hooke's Law to solve our given problem.
Substituting this value in our integral, we will get:
Using power rule, we will get:
We know that 6 inches is equal to 0.5 feet.
Work needed to stretch it beyond 6 inches beyond its natural length would be
Using power rule, we will get:
Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.
Answer:
39.473%
Step-by-step explanation:
It is actually fairly simple to get the answer to this. What you can do to find any percentage, is to take the amount done, or whatever it is in the scenario, and divide it by the total. It is like turning it into a fraction, which you can do as well. Turn this into a fraction, and then convert it. 15/38, 15 divided by 38 = 39.473.
Hope this helped ^-^
1 ounce =28.35g so 28.35g x 12 = 340.19g hope this helps