Question:
Solve the equation 2x2−5x+3=0 by the method of completing square.
Answer:
We have,
2x2−5x+3=0
⇒x2−25x+23=0 (Dividing throughough by 2)
⇒x2−25x=−23 (Shifting the constant term on RHS)
⇒x2−2(45)x+(45)2=(45)2−23 (Adding (21Coeff.ofx)2 onboth sides)
⇒(x−45)2=1625−23⇒(x−45)2=16
Answer:
g(x) = 1/3 (x - 12) .. vertical compression with factor 1/3 from f(x-4)
Step-by-step explanation:
*f(x) = x - 8 ... horizontal translation right 8 units from parent function f(x)=x
f(x-4) = (x-4) - 8 = x - 12 .... horizontal translation right 4 units from f(x)=x-8
g(x) = 1/3 (x - 12) .. vertical compression with factor 1/3 from f(x-4)
Answer: 13.7 in²
<u>Step-by-step explanation:</u>
Area of Square:
A = s²
= 8²
= 64
Area of Circle:
A = π r²
= π (4)²
= 16π
≈ 50.3
Area of Square - Area of Circle:
64 - 50.3 = 13.7
Answer:
yeah, well y=x/r-s
Step-by-step explanation:
well yeah, I just need words to upload yeah..
Answer:
let the two numbers be x and y
x+y=45(equation 1)
x-y=5(equation 2)
from equation (1) y=45-x(equation 3)
substitute 45-x for y in equation 2
x-(45-x)=5
x-45+x=5
x+x-45=5
2x-45=5
2x=45+5
2x=50
x=50/2
x=25
