Quadratic Equations in Single Variable
n²-3n+10=0
2x²+2x+1=0
25b²-16=0
f²-3f+2=0
1/3m +2m=4
a²=225
Linear Equation in single Variable
8-3k=12
5w+5=0
10u-5=8
Linear Equation in Two Variable
2y-z=9
3r+2e=6
d=3e-7
<h3>What is an equation?</h3>
It should be noted that an equation simply means the expression that's used to show the relationship between the variables.
In this case, the equation has been grouped.
Learn more about equations on:
brainly.com/question/2972832
#SPJ1
Group the given equations into two based on observed common properties.
Equations
n²-3n+10=0
8-3k=12
2y-z=9
2x²+2x+1=0
25b²-16=0
3r+2e=6
5w+5=0
f²-3f+2=0
d=3e-7
1/3m +2m=4
10u-5=8
a²=225
Answer:
<h2>x = 28</h2><h2>CE = 132</h2><h2 />
Step-by-step explanation:
|<------------- CE -------------------->|
C-------------------D-------------------E
2x + 10 3x - 18
2x + 10 = 3x - 18
2x - 3x = -18 - 10
-x = -28
x = 28
CE = 2x + 10 + 3x - 18
CE = 2(28) + 10 + 3(28) - 18
CE = 56 + 10 + 84 - 18
CE = 132
Answer:
x > 0
Step-by-step explanation:
Domain of a function is defined by the set of x-values of the graph of a function.
From the graph attached,
x-values are starting from x > 0 [Since x ≠ 0] and moves towards infinity,
Therefore, domain of the function will be,
(0, ∞) Or x > 0
Since <span> sin(α) > 0 and cos(α) > 0
so </span><span>α is IN THE FIRST QUADRANT (I)</span>
Answer:
x^ (5/3) y ^ 1/3
Step-by-step explanation:
Rewriting as exponents
(x^5y) ^ 1/3
We know that a^ b^c = a^(b*c)
x^ (5/3) y ^ 1/3