Answer:
If it is ax^2 + bx + c = 0 then it is a quadratic equation
Step-by-step explanation:
Answer:
5, 25, 45
Step-by-step explanation:
okay so it goes like this, the number in the x colume X 4 + 5 so 0 X 4 = 0 + 5 = 5, 5 X 4 is 20 + 5 = 25 and 10 X 4 =40 + 5 = 45.
Are you asking something?? Or did you just answer your own question? EITHER WAY. Pretty chill... should give me brainliest if you’re up for it ;)
Answer: 113 inches
Step-by-step explanation:
To solve the question, we have to find the perimeter of a circle since the skirt is circular. This will be:
Perimeter = 2πr
where
π = 3.142
r = diameter/2 = 36/2 = 18
The closest measurement needed for the sequin trim will then be:
= 2πr
= 2 × 3.142 × 18
= 113.112
= 113 inches
Answer:
Equation = (x - 6 )² + ( y + 3 )² = 9
Step-by-step explanation:
The circle passes through ( 6, 0) and ( 6 , -6)
They are the coordinates of the diameter.
Using this we can find the centre of the circle.
<u>Find the centre of the circle.</u>
Centre of the circle is the mid- point of (6, 0) and ( 6, -6)


<u>Find the radius of the circle.</u>

Diameter is the distance between the points (6 , 0) and ( 6, - 6)


Therefore,

<u>Standard equation of a circle:</u>
<u></u>
<u></u>
Therefore , equation of the circle ;
