<BOA = 360 -250 = 110
<<span>BDA = 110/2 = 55
<</span><span>BCA = 360 - (90+90+110)
</span><<span>BCA = 360 - 290
<</span><span>BCA = 70</span>
Let Susan's present age be x
Now, after 7 years ( her age will become 7 +x then) she'll be 2 as old she was 3 years ago.
Her age 3 years ago must be x-3
Now according to question,
twice Her age 3 years ago = her age after 7 years
now,
2(x-3) = 7+x
2x-6 = 7+x
2x-x =7+6
x = 13
x = 13
Therefore, her age presenr age is 13 years.
Well you use PEMDAS (1. Parentheses 2. Exponents 3. Multiplication and Division in order from left to right 4. Addition and Subtraction in order from left to right) to solve. you have no parentheses or exponents so you do multiplication and division first 14*14 = 196, and 196/14 is 14. Then you do addition and subtraction. 14 + 14 = 28. 28 - 14 = 14.
Answer:
Step-by-step explanation:
E is the midpoint of Ac & D is the midpoint of AB
DE = (1/2)BC {Midpoint theorem}
2*x + 2*1 = 4x - 6
2x + 2 = 4x - 6
Add 6 to both sides
2x + 2 + 6 = 4x
2x + 8 = 4x
Subtract 2x from both sides
8 = 4x - 2x
2x = 8
Divide both sides by 2
x = 8/2
x = 4
