<em>V = 120 in^3</em>
<u><em>Here is why:</em></u>
The volume formula for a pyramid is:

The B stands for the area of the base, which in this case is a right triangle. We will find the area of the right triangle first, then plug it into the equation.
The area formula for a triangle is:

Plug in the numbers.

A = 45
Now we have found the area of B, we can plug it into the volume formula for the pyramid.

V = 120 in^3
I think you forgot to mention Susan's current age if not:
x+5
x-4
6x
Answer:
over 9000
^^^
Liar.
Step-by-step explanation:
over 9000
^^^
Liar.
Answer:

Step-by-step explanation:
<u>Given </u><u>:</u><u>-</u><u> </u>
We know that the tangents are perpendicular to the radius at the point of contact . And here OLMN is a quadrilateral. Also we know that , the angle sum property a triangle is 360° .
<u>According</u><u> to</u><u> question</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Hence</u><u> the</u><u> </u><u>value</u><u> of</u><u> x</u><u> </u><u>is </u><u>6</u><u>3</u><u>°</u><u> </u><u>.</u>
Answer: 1.509
Step-by-step explanation:
The formula of Margin of Error for (n<30):-

Given : Sample size : n= 22
Level of confidence = 0.99
Significance level : 
Using the t-distribution table ,
Critical value : 
Standard deviation: 
Then, we have

Hence, the margin of error for a 99% confidence interval for the population mean =1.509