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givi [52]
3 years ago
6

In Figure 1, the area of square A is 9 square units, the area of square B is 16 square units, and the area of square C is 25 squ

are units. In Figure 2, the area of square D is 36 square units and the area of square E is 64 square units, and the area of square F is 100 square units. In Figure 3, the area of square G is 25 square units and the area of square H is 144 square units, and the area of square I is 169 square units. What can be concluded about the areas of the squares? A. The sum of the areas of the two smaller squares is less than the area of the larger square. B. The sum of the areas of the two smaller squares is greater than the area of the larger square. C. The sum of the areas of the two smaller squares is equal to the area of the larger square. D. The sum of the areas of the two smaller squares is equal to the area of the triangle.
Mathematics
2 answers:
weqwewe [10]3 years ago
7 0

Answer:

C. The sum of the areas of the two smaller squares is equal to the area of the larger square.

Step-by-step explanation:

9 + 16 = 25

36 + 64 = 100

25 + 144 = 169

The relations "less than" and "greater than" can be ruled out. These observations are consistent with selection C.

The triangle area is half the product of the square roots of the squares on the legs, so the areas of the triangles are (respectively) 6, 24, 30. These are not related to the sum of the smaller squares, so the last selection can also be ruled out.

gtnhenbr [62]3 years ago
7 0

Answer:

A. The sum of the areas of the two smaller squares is equal to the area of the larger square.

Step-by-step explanation:

In Figure 1, a, b, and c form the sides of PQR. They also form the sides of square A, square B, and square C respectively.

For a right triangle, the Pythagorean theorem states that the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Applying the Pythagorean theorem to PQR, it can be seen that a2 + b2 = c2.

Similarly, the following statements will be true for XYZ and STU.

For XYZ, d2 + e2 = f2.

For STU, g2 + h2 = i2.  

By observation, along with the Pythagorean theorem, the sum of the areas of the two smaller squares is equal to the area of the larger square.

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A retailer planned to buy some computers from a total of sh 1800000. Before the retailer could buy the computers the price per u
Alex Ar [27]

Answer:

50 computers

Step-by-step explanation:

After reduction, he bought x computers hence price per unit was 1800000/x

Before reduction, price per unit was 1800000/(x-5)

The difference in the price is 4000 hence

\frac {1800000}{x}-\frac {1800000}{x-5}=4000\\4x^{2}-20x+9000=0\\x^{2}-5x+2250=0\\(x+45)(x-50)=0\\x=50 or -45

Therefore, x=50

3 0
3 years ago
Constance works as a landscaper. She charges $100 per job and $10 for each hour, h, she works. Which expression represents the t
MissTica
B. 100+10h is the correct expression to represent how much the landscaper charges.
4 0
3 years ago
Jake is wrapping a gift that is in a box with the following dimensions.
nordsb [41]

Answer: 8

Step-by-step explanation: first multiply 12x4x8 for jakes gift. that is 384

then make each of the dimensions twice as large. so havanas dimensions would be. 24x8x16

24x8x16=3,072

last divide 3,072 by 384 and the answer would be 8

Havana's box is 8 times larger.

4 0
2 years ago
Read 2 more answers
a bag contains 10 white gold balls and 6 striped golf balls. a golfer wants to add 112 golf balls to the bag. he wants the ratio
wolverine [178]

Answer:70 white golf balls and 42 striped golf balls

Step-by-step explanation:

First we find the ratio of white to striped balls

White golf balls = 10

Striped golf balls = 6

Ratio = 10/6 = 5/3

We are told a golfer wants to add extra 112 balls to the already 16 balls

And the ratio after adding 112 balls must stay the same

First we label the extra golf balls to be added x and y

x = white golf balls

y = striped golf balls

So since we know the 112 balls added is a combination of the extra white golf balls and striped golf balls, we create an equation for that, labelling it (1)

x + y = 112 (1)

And we are told that after putting these extra balls the ratio must remain the same, which is 5/3

which will be (10 white balls + x) divided by (6 striped ball + y) will be equals to 5/3

So we create another equation for this, labelling it (2)

(10+x)/(6+y) = 5/3 (2)

So we have two simultaneous equations

We pick (1)

x + y = 112

We either make x or y the subject of formula, I choose to make x the subject of formula, we label the equation (3)

take y to the other side, causing it to change to -y

x = 112 - y (3)

We then work with (2)

(10+x)/(6+y) = 5/3

We cross multiply

3(10+x) = 5(6+y)

We open the brackets

Making the equation simplified and labelling it (4)

30 +3x = 30 + 5y

Collect like terms

3x -5y = 30-30

3x -5y = 0 (4)

Remember from (3) we know that

x = 112 -y

So we put (3) in (4)

3(112 - y) - 5y = 0

Open bracket

336 -3y -5y =0

336 -8y = 0

Transfer -8y to the other side, changing to +8y

336 = 8y

Divide both sides by 8

336/8 = y

42 = y

y = 42

from (3) we know that x equals 112 - y

So we put y = 42 in (3)

x = 112 - y

x = 112 -42 = 70

x = 70

So therefore number of white golfs balls and striped golfs balls to be added to keep the same ratio is 70 and 42 respectively

4 0
3 years ago
Is y=-x-3 and y=-3-x the same thing?
Musya8 [376]
YES ,it is same because it is on the same side, it's just switch the place. :)
6 0
3 years ago
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