Evaluate 7 sigma n=1 2(-2)^n-1
2 answers:
Okay I think you mean the sum of the first 7 terms of the geometric sequence:
a(n)=2(-2)^(n-1)
The sum of any geometric sequence is:
s(n)=a(1-r^n)/(1-r) in this case:
s(7)=2(1--2^7)/(1-7)
s(7)=-43
\[\sum_{n=1}^{7} 2(-2)^{n-1}\]
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