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Xelga [282]
3 years ago
9

Help... Please and Thank you

Mathematics
2 answers:
kirill115 [55]3 years ago
7 0

Answer:

The standard form is ⇒ y = -4x² - 32x - 77

Step-by-step explanation:

* Lets look to the vertex form y = a(x - h)² + k

 and the standard form y = ax² + bx + c, then equate them

∵ a(x - h)² + k = ax² + bx + c ⇒ solve the bracket

∴ a(x² - 2hx + h²) + k = ax² + bx + c ⇒ open the bracket

∴ ax² -2ahx + ah² + k = ax² + bx + c

* Now lets equate the like terms

∴ a = a ⇒ (1)

∴ -2ah = b ⇒ (2)

∴ ah² + k = c ⇒ (3)

* Lets do the same with the problem

∵ y = -4(x + 4)² - 13

∴ a = -4 , h = -4 , k = -13

* Use (1) , (2) and (3) to find a , b , c

∴ a = -4

∵ b = -2ah

∴ b = -2(-4)(-4) = -32

∵ c = ah² + k

∴ c = (-4)(-4)² + (-13) = -64 + -13 = -77

* Now we can write the standard form y = -4x² - 32x - 77

Kruka [31]3 years ago
6 0

Answer: y=-4x^2-32x-77

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