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nevsk [136]
3 years ago
5

Which chemical reaction falls under the study of electrochemistry?

Chemistry
2 answers:
viva [34]3 years ago
6 0
B. Zn(s)+Cu^2+(aq)-> Zn^2+(aq)+Cu(s) 
its the correct answer on    ed gen uity
disa [49]3 years ago
3 0
The chemical reaction <span>b) Zn(s) + Cu^2+(aq) --> Zn^2+(aq) + Cu(s) falls under the study of electrochemistry as it involve ions dissolved in solution. these are electrolytic solutions capable of transferring eletrons. </span>
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Which of the following statements about the water cycle is TRUE?
Evgesh-ka [11]

Answer:

the first one I believe is right but I could be wrong.

4 0
3 years ago
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I need to know the answer to that
Tresset [83]

im not sure which one to answer, and i can hardly see the text.

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3 years ago
Give two reasons why scientists create models to study atoms.
mariarad [96]
IT will be easy to know how chemical reactions occur
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4 0
3 years ago
What is the stoichiometric coefficient for oxygen when the following equation is balanced using the lowest whole-number coeffici
rodikova [14]

Answer:

Option (B) 7

Explanation:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

To know the coefficient of O2 in the above equation, let us balance the equation.

The above equation can be balance as follow:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)

There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + 3H2O(l)

There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:

C3H6O2(l) + 7/2O2(g) → 3CO2(g) + 3H2O(l)

Multiply through by 2

2C3H6O2(l) + 7O2(g) → 6CO2(g) + 6H2O(l)

Now, the equation is balanced.

From the balanced equation above, the coefficient of O2 is 7.

7 0
3 years ago
Mercury can be obtained by reacting mercury(I) sulfide with calcium oxide. How many grams of calcium oxide are needed to produce
OLga [1]
First, 55 g of Hg is 3.65 moles because one mole of Hg has a molar mass of 200.59

Then, the mole ratio of Hg to CaO is 8:4 or 2:1. SO we divide 3.65 by 2 to get 1.82 moles of CaO

This is the same as 102.06 grams because one mole of CaO has a molar mass of 56.0774

Hope this helps!
4 0
3 years ago
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