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3 years ago

Which chemical reaction falls under the study of electrochemistry?

Chemistry

2 answers:

viva [34]3 years ago

6 0

B. Zn(s)+Cu^2+(aq)-> Zn^2+(aq)+Cu(s)
its the correct answer on ed gen uity

disa [49]3 years ago

3 0

The chemical reaction <span>b) Zn(s) + Cu^2+(aq) --> Zn^2+(aq) + Cu(s) falls under the study of electrochemistry as it involve ions dissolved in solution. these are electrolytic solutions capable of transferring eletrons. </span>

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what concentration in parts per million in a solution that contains .008 grams of o2 dissolved in 1000 grams of water

julia-pushkina [17]

Ppm = mass of solute mg / mass of solvent kg

0.008 * 1000 = 8.0 mg ( solute )

1000 / 1000 = 1.0 kg (solvent )

ppm = 8 / 1

= 8.0 ppm

hope this helps!

7 0

3 years ago

At a certain temperature, 0.760 mol SO3 is placed in a 1.50 L container. 2SO3(g) = 2SO2(g) + O2(g)At equilibrium, 0.130 mol O2 i

olganol [36]

Answer:

$K_c=0.0867$

Explanation:

Moles of SO₃ = 0.760 mol

Volume = 1.50 L

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.760}{1.50\ L}$

[SO₃] = 0.5067 M

Considering the ICE table for the equilibrium as:

$\begin{matrix} & 2SO_3_{(g)} & \rightleftharpoons & 2SO_2_{(g)} & + & O_2_{(g)}\\At\ time, t = 0 & 0.5067 &&0&&0 \\ At\ time, t=t_{eq} & -2x &&2x&&x \\----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:- &0.5067-2x&&2x&&x\end{matrix}$

Given:

Equilibrium concentration of O₂ = 0.130 mol

Volume = 1.50 L

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.130}{1.50\ L}$

[O₂] = x = 0.0867 M

[SO₂] = 2x = 0.1733 M

[SO₃] = 0.5067-2x = 0.3334 M

The expression for the equilibrium constant is:

$K_c=\frac {[SO_2]^2[O_2]}{[SO_3]^2}$

$K_c=\frac{(0.3334)^2\times 0.0867}{(0.3334)^2}$

$K_c=0.0867$

5 0

3 years ago

Help?? help for mee??? maybe? what if i said...please????

Bezzdna [24]

Answer:

Explanation:

because they transfer an electron the sodium ion has a positive charge, and the chlorine ion has a negative charge so one gives off positive and one gives of negative

3 0

2 years ago

The atomic masses of elements X and Y will always equal the exact atomic mass of Z

tamaranim1 [39]

$A_r(x)+A_r(y)=A_r(z)$