Explanation:
(a)
The given data is:-
Energy = 2391 Calories
The conversion of calories to J is shown below as:-
1 calorie = 4.184 J
So,
Energy = 4.184 * 2391 J = 10003.944 J
Answer in four significant digits: - 
(b)
The conversion of calories to kJ is shown below as:-
1 calorie = 0.004184 kJ
So,
Energy = 0.004184 * 2391 kJ = 10.003944 kJ
Answer in four significant digits: - 
(c)
The conversion of calories to kWh is shown below as:-
1 calorie = 
kWh
So,
Energy = 
kWh = 0.002778873 kWh
Answer in four significant digits: - 
I dont get it someone please help
Answer:
0.0159m
Explanation:
9 M
Explanation:
Lead(II) chloride,
PbCl
2
, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.
Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,
K
sp
, will be established between the solid lead(II) chloride and the dissolved ions.
PbCl
2(s]
⇌
Pb
2
+
(aq]
+
2
Cl
−
(aq]
Now, the molar solubility of the compound,
s
, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.
Notice that every mole of lead(II) chloride will produce
1
mole of lead(II) cations and
2
moles of chloride anions. Use an ICE table to find the molar solubility of the solid
PbCl
2(s]
⇌
Pb
2
+
(aq]
+
2
Cl
−
(aq]
I
−
0
0
C
x
−
(+s)
(
+
2
s
)
E
x
−
s
2
s
By definition, the solubility product constant will be equal to
K
sp
=
[
Pb
2
+
]
⋅
[
Cl
−
]
2
K
sp
=
s
⋅
(
2
s
)
2
=
s
3
This means that the molar solubility of lead(II) chloride will be
4
s
3
=
1.6
⋅
10
−
5
⇒
s
= √
1.6
4
⋅
10
−
5 =
0.0159 M
Answer:
Chromatography uses chromatography paper which is filter paper that is made of cellulose, a polymer. Cellulose is polar, therefore it attracts water molecules, as well as other polar substances. As the solvent reacts with the paper, it competes for the attraction of the molecules being separated.
Explanation:
hope it helps
