We are given the amount of Nitrogen gas and hydrogen gas reacted to form ammonia:
N2 = 19.25 grams
H2 = 11.35 grams
Set-up a balanced chemical equation:
N2 + 3H2 ==> 2NH3
The theoretical amount of ammonia that will be produced from the given amounts is:
First, we need to determine the limiting reactant to serve as our basis for calculation.
number of moles / stoichiometric ratio
N2 = 19.25 g/ 28 g/mol / 1 = 0.6875
H2 = 11.35 g/ 2 g/mol /3 = 1.89
The limiting reactant is N2.
0.6875 moles N2 * (2 NH3/ 1 N2) * 17 g/mol NH3
The amount of NH3 produced is 23.375 grams of ammonia. <span />
Answer:
P1 =4 atm
T1= 20°C
P2=1 atm
T2=?
According to Gay-Lussac's Law or Third Gas Law,
P1T2=P2T1
4×T2=1×20
T2= 20/4
T2= 5°C
Answer At 5°C temperature does a gas at 1.00 atm !
Answer:
1.55
Explanation:
-log(M)=pH
- Hope that helps! Please let me know if you need further explanation.
Option C: Sulfur Dioxide is the answer
Hope this helps
