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Nezavi [6.7K]
2 years ago
9

At short company has initial costs of $800 per month and it costs them $1.50 per shirt. Let y represent the cost to run the comp

any each month and x to represent the number of T-shirt's made each month A. Find the linear equation that models the cost of the t shirt company. B. Write a complete sentence explaining the y intercept in this application. C. Write a complete sentence explaining the meaning of the slope in this application.
Mathematics
1 answer:
adelina 88 [10]2 years ago
4 0

Answer:

A. y = $800 + $1.50x

B. The cost to run the company each month = y

C. The initial cost ($800) plus the cost of each t-shirt ($1.50) and the number of t-shirts (x)

Step-by-step explanation:

I hope this helps :)

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Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

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