To answer the question above, we will have to use some calculus approach to this problem.
<span>volume of sphere = (4/3)(pi)(radius^3) = (4/3)(pi)(9^3) = 972pi </span>
<span>mass = (density)(volume) = (972pi)(1,000) = 972,000pi </span>
<span>force = (mass)(acceleration or gravity here) = (972,000pi)(9.8) = 9,525,600pi </span>
<span>work = (force)(distance) = (9,525,600pi)(4.5) = 42,865,200pi J
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I hope my answer helped you with your problem
Look in the attached file to see answer
The answer is (5p+6q)(5p-6q)
Steps:
Apply difference of the squares rule: x^2-y^2=(x+y)(x-y)
25p^2-36q^2=(5p+6q)(5p-6q)
Hope this helps you! (:
-PsychoChicken4040
The answer is 1 over 3(3.14)(5²)(8)
The volume of the cylinder (V1) is:
V1 = π · r² · h (r - radius, h - height)
The volume of the cone (V2) is:
V2 = 1/3 π · r² · h (r - radius, h - height)
It is given:
r = 5 feet
h = 8 feet
π = 3.14
Therefore, the volume of the cone is:
V2 = 1/3 · 3.14 · 5² · 8 which is the same as 1 over 3(3.14)(5²)(8).
11z/16+7z/8=5/16
(11z+14z)/16=5/16
25z=5
z=5/25=1/5
