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tatyana61 [14]
3 years ago
15

Pls help, 7th grade math, Will give brainliest

Mathematics
1 answer:
sveta [45]3 years ago
3 0

Answer:

I'm sorry I don't know

Step-by-step explanation:

but maybe next week I'll be able to answer you

You might be interested in
If f (x) = 5 x minus 25 and g (x) = one-fifth x + 5, which expression could be used to verify g(x) is the inverse of f(x)?
Vinil7 [7]

Answer:

The expression used to represent g(x) as inverse of f(x) is \frac{1}{5}(5x-25)+5

Option B is correct.

Step-by-step explanation:

We are given:

f(x)= 5x-25\\g(x)=\frac{1}{5}x+5

We need to find the expression that could be used to verify g(x) is the inverse of f(x).

We know that g(f(x))=x is inverse of function

So placing value of f(x) in g(x)

g(f(x))=\frac{1}{5}(5x-25)+5

So, the expression used to represent g(x) as inverse of f(x) is \frac{1}{5}(5x-25)+5

Option B is correct.

We can also solve to prove that g(f(x))=x

g(f(x))=\frac{1}{5}(5x-25)+5\\g(f(x))=\frac{5}{5}(x-5)+5\\g(f(x))=x-5+5\\g(f(x))=x

5 0
2 years ago
Read 2 more answers
Simplify 5y^-2<br><br> please help fast!!!
Semmy [17]

Answer:

25y2 i think

Step-by-step explanation:

i hope it helps

4 0
1 year ago
Read 2 more answers
Multiply (x-2) (2x+4)
Bas_tet [7]

Answer:

2x {}^{2}  - 8 = 0

Step-by-step explanation:

(x-2) (2x+4)  = 0\\ 2x {}^{2}   +  4x - 4x - 8 = 0 \\ 2x {}^{2}  - 8 = 0

5 0
3 years ago
What is the measure of an exterior angle of a rectangle of a regular 11-sided polygon?
horsena [70]

180 \div 11 =
4 0
3 years ago
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Let g(x) = f(x+3) for some function f(x). Is g(x) a function? From the previous problem, let the domain of f(x) be [1, 4). What
padilas [110]

The domain of g(x) is [4, 7)

<h3>How to determine the domain of g(x)?</h3>

The function is given as:

g(x) = f(x + 3)

Since f(x) is a function, then g(x) is also a function

The domain of f(x) is given as:

[1, 4)

The equivalent of these values in g(x) are

x = 1 + 3 = 4

x = 4 + 3 = 7

Hence, the domain of g(x) is [4, 7)

Read more about domain at

brainly.com/question/1770447

#SPJ1

7 0
1 year ago
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