Answer:
x = -3 and x = -3/2
Step-by-step explanation:
After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:
p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>
p(x) = x^2(2x+3) <u>-9(2x+3)</u>
Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:
p(x) = (x^2 - 9)(2x+3)
Factor it once more because there's a difference of squares:
p(x) = (x+3)(x-3)(2x+3)
Now just plug in whatever makes the each bracket equal 0:
x = -3, x = 3, and x = -3/2
Those are your zeros.
Answer:
ask the internet this question sorry not being rude its becausd no ones answered it
Answer:
Step-by-step explanation:
we know that
The volume of a right circular cone is equal to
where
r is the radius of the base of the cone
h is the height
Solve for r-----> That means, isolate the variable r
so
step 1
Multiply by 3 both sides
step 2
Divide by 
both sides
step 3
take square root boot sides
The two questions aren’t there?
