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Artist 52 [7]
3 years ago
9

A cylindrical cooler has a diameter of 30 inches and a height of 24 inches . If a cup has a diameter of 3 inches and a height of

4 inches about how many full cups could be able to be filled from the cooler ?
Mathematics
2 answers:
Aleks04 [339]3 years ago
8 0

Answer:

The answer to your question is 600 cups

Step-by-step explanation:

Data

Cylinder                            Cup

diameter = 30 in               diameter = 3 in

height = 24 in                    height = 4 in

Process

1.- Calculate the volume of the cylinder

Volume = πr²h

-Substitution

Volume = (3.14)(30/2)²(24)

-Simplification

Volume = (3.14)(15)²(24)

Volume = (3.14)(225)(24)

-Result

Volume = 16959 in³

2.- Calculate the volume of the cup

Volume = (3.14)(3/2)²(4)

-Simplification

Volume = (3.14)(1.5)²(4)

Volume = (3.14)(2.25)(4)

-Result

Volume = 28.26 in³

3.- Divide the volume of the cylinder by the volume of the cup

Number of full cups =  16959 in³ /  28.26 in³

Number of full cups = 600

hram777 [196]3 years ago
6 0

Answer: 600 full cups

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

Considering the cylindrical cooler,

Diameter = 30 inches

Radius = diameter/2 = 30/2

Radius = 15 inches

Height = 24 inches

Therefore,

Volume of cylindrical cooler =

3.14 × 15² × 24 = 16956 inches³

Considering the cup

Diameter = 3 inches

Radius = 3/2 = 1.5 inches

Height = 4 inches

Therefore,

Volume of can = 3.14 × 1.5² × 4 = 28.26 inches³

Therefore, the number of full cups that can be filled from the cooler is

16956/28.26 = 600

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3 years ago
A violin student records the number of hours she spends practicing during each of nine consecutive weeks: 6.2 5.0 4.3 7.4 5.8 7.
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A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first  quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

Step-by-step explanation:

Assuming this complete question: A violin student records the number of hours she spends practicing during each of nine consecutive weeks:

6.2 5.0 4.3 7.4 5.8 7.2 8.4 1.2 6.3

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The third quartile would be 7.2 since we analyze 6.2, 6.3, 7.2, 7.4, 8.4 and the middle point is 7.2

Then the interquartile rnage would be:

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The lower limit on this case would be:

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And our value is 1.2 is lower than the lower limit 1.7

Considering the smallest data value (1.2) and using the 1.5 × IQR rule, we would:

A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first  quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

B) not classify the value 1.2 as an outlier, because it is not more than 1.5 × IQR below  the first quartile.

False 1.2 is more than 1.5 IQR below the first quartile

C) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the  median.

False, we analyze if is an outlier comparing with the Q1 or Q3 not with the median

D) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the  mean.

False we analyze if is an outlier comparing with the Q1 or Q3 not with the mean

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