Answer:
100
Step-by-step explanation:
Okay so I'm not 100% sure but I think it's 100 because:
Angle B and D are the same, so the 12.5 areas will be the same (I honestly suck at explaining I'm really sorry.) But, if you add the sides from angle B and D it will be 50 because 12.5 + 12.5 + 12.5 + 12.5 (or 12.5 * 4). Meanwhile, For angle A and C, both outsides are the same as the other side.
I'm so sorry I can't explain the problem well but once you add them:
11.5 + 11.5 + 12.5 + 12.5 + 12.5 + 12.5 + 13.5 + 13.5 = 100
Answer:
True
Step-by-step explanation:
We can sue the pythagorean theorem to verify. 15^2+36^2 should equal the longest side squared or 39^2. If we plug in the numbers, it checks out!
2.8M/(365x24x60)=wonder why you need this
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an
S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d] → Equation (1)
S=an+an−1+an−2+an−3+...+a1
S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d] → Equation (2)
Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)
2S=n(a1+an)
S=n/2(a1+an)
Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
