1055 is what i got. have a good day!
Answer:
Since Darcie wants to crochet a minimum of 3 blankets and she crochets at a rate of 1/5 blanket per day, we can determine how many days she will need to crochet a minimum of 3 blankets following the next steps:
- Finding the number of days needed to crochet one (1) blanket:
\begin{gathered}1=\frac{1}{5}Crochet(Day)\\Crochet(Day)=5*1=5\end{gathered}
1=
5
1
Crochet(Day)
Crochet(Day)=5∗1=5
So, she can crochet 1 blanket every 5 days.
- Finding the number of days needed to crochet three (3) blankets:
If she needs 5 days to crochet 1 blanket, to crochet 3 blankets she will need 15 days because:
\begin{gathered}DaysNeeded=\frac{NumberOfBlankets}{Rate}\\\\DaysNeeded=\frac{3}{\frac{1}{5}}=3*5=15\end{gathered}
DaysNeeded=
Rate
NumberOfBlankets
DaysNeeded=
5
1
3
=3∗5=15
- Writing the inequality
If she has 60 days to crochet a minimum of 3 blankets but she can complete it in 15 days, she can skip crocheting 45 days because:
AvailableDays=60-RequiredDaysAvailableDays=60−RequiredDays
AvailableDays=60-15=45DaysAvailableDays=60−15=45Days
So, the inequality will be:
s\leq 45s≤45
The inequality means that she can skip crocheting a maximum of 45 days since she needs 15 days to crochet a minimum of 3 blankets.
Have a nice day!
What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
M>5=m>4
m>5 and m>7 are on line then m>5+m>7=180
by substituting
m>4+37=180
m>4=143
m>2=m>7=37
m>4=m>8
m<3+m>5=180
