<span>You have:
- The diameter of the cylinder is 12 inches and its height is 14 inches.
-The height of the cone is 6 inches.
So, you must apply the formula for calculate the volume of the cylinder a the formula for calculate the volume of a cone.
V1=</span>πr²h
<span>
V1 is the volume of the cylinder.
r is the radius.
h is the height (h=14 inches)
The problem gives you the diameter, but you need the radius, so you have:
r=D/2
r=12 inches/2
r=6 inches
When you substitute the values into the formula, you obtain:
V1==</span>πr²h
V1=(3.14)(6 inches)²(14 inches)
V1=1582.56 inches³<span>
The volume of the cone is:
V2=(</span>πr²h)/3
<span>
V2 is the volume of the cone.
r is the radius (r=6 inches)
h is the height of the cone (h=6 inches).
Then, you have:
</span>
V2=(πr²h)/3
V2=(3.14)(6 inches)²(6 inches)/3
V2=226.08 inches³
<span>
Therefore, </span>the volume of the cake<span> (Vt) is:
Vt=V1+V2
Vt=</span>1582.56 inches³+226.08 inches³
<span> Vt=1808.6 inches</span>³
Answer:
(g o f)(x) = 
(not simplified)
Step-by-step explanation:
(g o f)(x) = g(f(x))
g(x) = 
f(x) = 
g(f(-5)) = g(
= 
= 
g(-170) = 
=
15 gggggggggggggggggggggg
Sense the two triangles are congruent you would use CPCTC.
I think the graph below is correct.
