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lidiya [134]
3 years ago
15

Please help me w the equation and please don’t take advantage of the points.

Mathematics
1 answer:
anyanavicka [17]3 years ago
5 0

Answer: y= 1 over 3x+5

Step-by-step explanation:

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BartSMP [9]

Answer:

Look 6th grade girl hi Do the work by yourself brainly not for 6th graders

8 0
3 years ago
Can you answer these please? Show all work
Ganezh [65]

Answer:

i)  Sally' s grocery bill = c - \frac{5}{100}c = 0.95c

   Therefore the correct option is B.)

ii)   Therefore the expression which represents the expected population  

    next year is given by :

    = p + \dfrac{7.5}{100} p   =   1.075p

Therefore the correct option is B.)

Step-by-step explanation:

Sally has a discount card that reduces the price of her grocery bill in a certain grocery store by 5%.

Let c represent the cost of Sally's groceries.

therefore the expression which represents Sally's grocery bill is given by :

Sally' s grocery bill = c - \frac{5}{100}c = 0.95c

Therefore the correct option is B.)

The population of a city is expected to increase by 7.5% next year If p represents the current population, which expression represents the expected population next year?

Let p = current population of a city.

Therefore the expression which represents the expected population next year is given by :

  = p + \dfrac{7.5}{100} p = 1.075p

Therefore the correct option is B.)

8 0
3 years ago
ANYTHING WOULD HELP (answer, how to set up, etc)
e-lub [12.9K]
.................... I’m sorry I can’t see it
7 0
3 years ago
Read 2 more answers
What is the b in equation y=2x+12
xxTIMURxx [149]

Answer:

b = 12

Step-by-step explanation:

y = mx + b

b = 12

6 0
3 years ago
Read 2 more answers
Most people complain that they gain weight during the December holidays. To find out how much, we sample the weights of 23 adult
kakasveta [241]

Answer:

The 88% confidence level for the average weight gain if between -1.30 lbs and 4.58 lbs.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 23 - 1 = 22

88% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 22 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.88}{2} = 0.94. So we have T = 1.6176

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.6176\frac{8.73}{\sqrt{23}} = 2.94

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.64 - 2.94 = -1.30 lbs

The upper end of the interval is the sample mean added to M. So it is 1.64 + 2.94 = 4.58 lbs

The 88% confidence level for the average weight gain if between -1.30 lbs and 4.58 lbs.

5 0
3 years ago
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