Answer:
1 / q^30.
Step-by-step explanation:
[(p^2)(q^5)]^-4 * [(p^-4)(q^5)]^-2
Using the law (a^b)^c = a^bc :-
= p^-8 * q^-20 * p^8 * q^-10
= p^(-8+8) * q^(-20-10)
= p^0 * q^-30
= 1 * q^-30.
= 1 / q^30.
40
count the blocks
Answer is attached.
Please check the image.
She has a 67% chance of getting anything other than a multiple of 3.
8 to 4
