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stiks02 [169]
3 years ago
8

-1/2 + (3/4 × 4/9) = ?

Mathematics
1 answer:
likoan [24]3 years ago
7 0

Answer:

-0.16666 and 6 repeats

Step-by-step explanation:

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The average weight of a mango, kiwi, peach and banana is 135 grams. The average weight of the mango, kiwi and peach is 120 grams
Kruka [31]

Answer:

200

Step-by-step explanation:

bruh truss me❤️

5 0
3 years ago
- 6x+4=-2 algebra question​
QveST [7]
You need to get x= something.

To do this, you -4 on both sides to leave you with just an x value on the left. This gives -6x=-6

Then you need x on its own, so you divide both sides by -6.

-6/-6= 1, so x=1
7 0
3 years ago
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09

The rate of increase after 1 day is 0.09

8 0
3 years ago
Find two solutions to the equation (x^3 − 64)(x^5 − 1) = 0.
Rashid [163]

Answer:

the two roots are x = 1 and x = 4

Step-by-step explanation:

Data provided in the question:

(x³ − 64) (x⁵ − 1) = 0.

Now,

for the above relation to be true the  following condition must be followed:

Either  (x³ − 64) = 0 ............(1)

or

(x⁵ − 1) = 0 ..........(2)

Therefore,

considering the first equation, we have

(x³ − 64) = 0

adding 64 both sides, we get

x³ − 64 + 64 = 0 + 64

or

x³ = 64

taking the cube root both the sides, we have

∛x³ = ∛64

or

x = ∛(4 × 4 × 4)

or

x = 4

similarly considering the equation (2) , we have

(x⁵ − 1) = 0

adding the number 1 both the sides, we get

x⁵ − 1 + 1 = 0 + 1

or

x⁵ = 1

taking the fifth root both the sides, we get

\sqrt[5]{x^5}=\sqrt[5]{1}

also,

1 can be written as 1⁵

therefore,

\sqrt[5]{x^5}=\sqrt[5]{1^5}

or

x = 1

Hence,

the two roots are x = 1 and x = 4

4 0
3 years ago
SOMEONE PLSSSS HELP!!!!!!!
kow [346]

Answer:

you can use desmos

Step-by-step explanation:

for example put x=88

and do the same with the rest

then put x+y+z and you will get your answer

6 0
3 years ago
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