Using the z-distribution, it is found that the 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The sample size and the estimate are given by:

Hence:


The 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).
More can be learned about the z-distribution at brainly.com/question/25890103
Answer:
Let t be the number of toys.
Since, the toy drive already has collected 300 toys
⇒ t+ 300
Also, it is given that the goal of a toy drive is to donate more than 1000 toys.
We get an inequality:
⇒
Solve an inequality:

Subtract 300 from both sides we get

Simplify:
t > 700
Therefore, more than 700 toys does the toy drive need to meet its goal.
An inequality is;
; t > 700
The supplement of 1/5 of a complete angle is 150degrees
Answer: Each notebook cost $2.55
Step-by-step explanation:
You divide $15.30 by 6, which equals $2.55.