When you graph a system of equations, the solution is always at the point at which the two lines intersect. So you have to find that point and then find which number it is on the x-axis and y-axis. Then you should write it in this form (X,Y)
So the lines basically cross at (1,2.5)
I’m not really sure if this is the correct answer but I hope it helps!!
Good luck!
Answer:
x = - 5
Step-by-step explanation:
Given
- 8x + 32 = 4(- 2 - 4x) ← distribute parenthesis on right side
- 8x + 32 = - 8 - 16x ( add 16x to both sides )
8x + 32 = - 8 ( subtract 32 from both sides )
8x = - 40 ( divide both sides by 8 )
x = - 5
Answer:
1100 in²
Step-by-step explanation:
Find the area of the boxes separately and add them
Answer:
11. your choices are correct
12. 132°
Step-by-step explanation:
11. The given equations can be (re)written to slope-intercept form. Only those lines with a slope of 2 will be parallel to the given line.
A: y = 2x -8 . . . . . slope = 2, an answer
B: y = -2x +1 . . . . . slope = -2, not an answer
C: y = -2x +7 . . . . .slope = -2, not an answer
D: y = 2x +2 . . . . . slope = 2, an answer
E: y = -2x -9 . . . . . slope = -2, not an answer
__
12. The marked angles are supplementary, so ...
(3x -6)° +(x +2)° = 180°
4x -4 = 180 . . . . . . . . . . . divide by °, collect terms
x -1 = 45 . . . . . . . divide by 4
x = 46 . . . . . . . . . add 1
Now, we can find the angle of interest.
∠PQR = (3x -6)° = (3·46 -6)°
∠PQR = 132°
Answer:
width = 3.5 m
length = 18 m
Step-by-step explanation:
area = length x width
x is the width then length = 2x + 11
x(2x + 11) = 63
2x^2 + 11x - 63 = 0
The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a
with a = 2
b = 11
c = -63
substitute in the formula
x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)
x = [-11 +/- √(121 + 504)]/4
x = [-11 +/- √625]/4
x = (-11 +/- 25)/4
x1 = (-11 + 25)/4 = 14/4 = 3.5
x2 = (-11 - 25)/4 = -36/4 = -9
since width can't be a negative number, x is 3.5
length = 2x + 11 = 2(3.5) + 11 = 18
