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2 years ago

How do you write 30 feet to 60 feet as a fraction and in lowest terms

Mathematics

2 answers:

Arte-miy333 [17]2 years ago

8 0

I think the answer would be 1/2

AveGali [126]2 years ago

7 0

30 to 60 = 30:60 = 30/60 = 1:2 = 1/2 = 0.5

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If RON becomes 181514 what becomes 122122?

goldfiish [28.3K]

Answer:

B. LUV

Step-by-step explanation:

its in the order of the alphabet 12-21-22

7 0

2 years ago

Read 2 more answers

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

5 0

2 years ago

If f(3)=2x^3 -2 , what is the value of f(2)

iris [78.8K]

I'm not sure about this but will give it a try:

Let f(n) = 2xⁿ - 2

Then f(3) = 2x³ - 2

So, f(2) = 2x² - 2

5 0

2 years ago

What is the volume? 2 mm 8 mm 4 mm cubic millimeters

shutvik [7]

Answer:

64 mm³

Step-by-step explanation:

I am assuming there was a photo to go with this problem

However the general formula to find volume is usually V = l×w×h

It does not matter which measurement is which because they all get multiplied together.
However assigning a name to each unit of measurement we will denoted the length (l) as 2 mm, the width (w) as 8 mm, and the height (h) as 4 mm
Plugging these values into the formula we get: V = (2)(8)(4) = 64 mm³

6 0

2 years ago

In the video, the water level was 15 milliliters before adding the chain, and 20 milliliters after adding the chain. When I weig

mr_godi [17]

Answer:

39.7%

Explanation:

1. First find the density of your chain

Density = mass / volume

Volume = displaced water volume

= Volume of Final level of water - initial level of water

= 20 ml - 15 ml = 5 ml

Mass = 66.7 g

Density = 66.7g / 5 ml = 13.34 g/ml

2. Second, write the denisty of the chain as the weighted average of the densities of the other metals:

Mass of gold × density of gold + mass of other metals × density of other metals, all divided by the mass of the chain.

Calling x the amount of gold, then the amount of other metals is 66.7 - x:

$\dfrac{19.3\cdot x+9.7\cdot (66.7-x)}{66.7}=13.34$

$19.3x+635.66-9.7x=889.778$

$9.6x=254.118\\\\x=26.47$

Then, there are 26.47 grams of gold in 66.7 grams of chain, which yields a percentage of:

(26.47 / 66.7) × 100 = 39.7%

7 0

2 years ago