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Artemon [7]
3 years ago
5

How many solutions are there to the equation 11x+25=7x+15

Mathematics
2 answers:
Vladimir [108]3 years ago
5 0
There is only one solution for this equation which is x = -2.5 11x+25=7x+15 11x+25-7x=15 11x-7x=15-25 4x= -10 x = -10/4 x = -5/2 x = -2.5
makkiz [27]3 years ago
3 0
Just one 11x+25=7x+15 11x - 7x = 15 -25 4x = -10 x = -10/4 x = -5/2
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5. 88 lb X 12 days<br> 1 day
AVprozaik [17]
70.56 is 5.88 x 12 but i’m not exactly sure what the question is... sorry
8 0
3 years ago
The CHS football game began at 7:30. It ended at 10:00. How long was the game?
klemol [59]
2Hrs 30Mins.
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6 0
2 years ago
This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t
mariarad [96]

Answer:

a. \frac{35}{51}

b. \frac{51}{100}

c. \frac{1}{5}

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C')  + n(B∩C')  + n(C∩C')  = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}

b. The proportion of municipal bonds are issued by cities = \frac{n(C')}{x}

=\frac{0.51x}{x}

=\frac{51}{100}

c. The proportion of municipal bonds are issued by suburbs = \frac{n(S)}{x}

=\frac{0.20x}{x}

=\frac{20}{100}

=\frac{1}{5}

3 0
2 years ago
The scale from a garden to this drawing is 8 ft to 1 cm. the scale from the same garden to another drawing is 2 ft to 1 cm. what
garik1379 [7]

The lengths of the base and height of the garden in the other scale drawing are 0.6 cm and 0.9 cm. So, option A is correct.

What is the scale factor?

The scale factor is calculated by                                                                     Scale factor = Length of the new drawing ÷ length of the original drawing

Calculation:

It is given that,

For the given triangle drawing, the scale from a garden to this drawing is 8 ft to 1 cm. The scale from the same garden to another drawing is 2 ft to 1 cm.

So, we can compute the scale factors as

8 ft to 1 cm = 1/8 cm

2 ft to 1 cm = 1/2 cm

Then the scale factor for the required lengths is 1/8 ÷ 1/2 = 1/4 cm

Thus, the required lengths are:

The base of the garden on the other scale drawing is

= 2.4 cm × 1/4

= 0.6 cm

The height of the garden on the other scale drawing is

= 3.6 cm × 1/4

= 0.9 cm

Therefore, the lengths of the base and the garden on the other scale drawing are 0.6 cm and 0.9 cm. So, option A is correct.

The given question in the portal was incomplete. Here is the complete question.

Question: The scale from a garden to this drawing is 8 ft to 1 cm. The scale from the same garden to another drawing is 2 ft to 1 cm. What are the lengths of the base and height of the garden in the other scale drawing?

A) 0.6 cm and 0.9 cm

B) 1.2 cm and 1.8 cm

C) 4.8 cm and 7.2 cm

D) 9.6 cm and 14.4 cm

Learn more about scale factors here brainly.com/question/28307342

#SPJ4

5 0
1 year ago
How many solutions does the equation have?
Andreyy89

Answer:

Since it is a linear equation, it has one solution.

step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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