How many solutions are there to the equation 11x+25=7x+15

2 answers:

5 0

There is only one solution for this equation which is x = -2.5 11x+25=7x+15 11x+25-7x=15 11x-7x=15-25 4x= -10 x = -10/4 x = -5/2 x = -2.5

makkiz [27]3 years ago

3 0

Just one 11x+25=7x+15 11x - 7x = 15 -25 4x = -10 x = -10/4 x = -5/2

You might be interested in

A person standing in the ground throws a ball onto a flat rooftop. The ball rolls around for several seconds. Then the ball fall

natali 33 [55]

Answer:

Graph D

Step-by-step explanation:

According to the question, the correct graph is D.

It's not A because, the ball is thrown after some pause and the ball doesn't roll on the roof, falls immediately.

It's not B or C because the ball goes up after reaching the roof but should fall down.

6 0

2 years ago

Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8

Dima020 [189]

Let $f(x,y,z)=x+y+z-8e^{xyz}$ . The tangent plane to the surface at (0, 0, 8) is

$\nabla f(0,0,8)\cdot(x,y,z-8)=0$

The gradient is

$\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)$

so the tangent plane's equation is

$(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8$

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by $t$ , then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

$(1,1,1)t+(0,0,8)=(t,t,t+8)$

or $x(t)=t$ , $y(t)=t$ , and $z(t)=t+8$ .

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)