Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3
Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10
what are their present ages
find M and N
substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:
4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14
M = 2(14) - 3 = 28 - 3 = 25
Mike is 25 and Nuke is 14.
check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10
Answer:
Yes, I can reject the null hypothesis with 95% confidence.
Step-by-step explanation:
Critical value t(63) = 1.99
p-value = 0.03
Confidence level (C) = 95% = 0.95
Significance level = 1 - C = 1 - 0.95 = 0.05
Conclusion:
Reject the null hypothesis because the p-value 0.03 is less than the significance level 0.05.
The other number could be 6. The GCF of 6 and 24 is 6, and 6 is less than 30.
Answer:
Tn=T1+(n-1)*d
Step-by-step explanation:
Tn is the nth term
T1 is the first term of the sequence
n is the nth term as well
d is the common difference
