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3 years ago

100 POINTS!!! Which statement about rational numbers is correct?

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

6 0

Answer: Rational numbers have decimal expansions that repeat or terminate.

Step-by-step explanation:

The explanation of this is the non-terminating but repeating decimal expansion means that although the decimal representation has an infinite number of digits, there is a repetitive pattern to it. The rational number whose denominator is having a factor other than 2 or 5, will not have a terminating decimal number as the result.

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Solve the system of equations by the substitution method. y = 5x + 6 y=9x+7.

joja [24]

Answer:

(-1/4, 19/4)

Step-by-step explanation:

5x+6=9x+7

-4x=1

x= -1/4

y=5(-1/4) +6

y=19/4

3 0

3 years ago

Here is a CD rack. One Rack holds 25 CD's. David has 83 CD's. Lin has 6 full racks of CD's. How many racks does David need to ho

Dimas [21]

If David has 83 CD's, and each rack holds 25, then David would need 4 racks. 4 racks will hold up to 100 CD's, where as 3 racks would only hold 75.

I'm not sure what 'Lin' has to do with this equation, but if she has 6 racks full of CD's then in total she has 150 CD's.

Hope this helps! :)

6 0

3 years ago

In JKL. solve for x 66.73 74.89 15.44 38.16

liq [111]

By right triangle trigonometry, the sine of the measure of an angle is the ratio of the opposite side of this angle to the hypotenuse.

Thus, $\displaystyle{\sin27^{\circ}= \frac{34}{x}$

$\sin27^{\circ}$ is a constant which can be found using a calculator:

with calc in pc: view → scientific → 27→sin = 0.45399,

thus x=34/0.45399=74.89

Answer: 74.89

5 0

3 years ago

Last week, Gina's art teacher mixed 9 pints of red paint with 6 pints of white

kherson [118]

Answer:

Step-by-step explanation:

First mix: 4 pints red and 3 pints white = 7 pints in 4:3 ratio.

Second mix: 5 pints red and 2 pints white = 7 pints in 5:2 ratio

Second music is redder than first mix.

4 0

3 years ago

(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions

Sliva [168]

$\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}$
$\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}$
$\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}$
$\frac{x+2+2x-1}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}$
$\frac{3x+1}{(x-1)(x+2)}= \frac{3(x^2+x-2)}{2}$
$\frac{}{(x-1)(x+2)}= \frac{3x^2+3x-6)}{2}$
$\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}$
$\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}$
$\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0$
$\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0$

this will be continued

5 0

3 years ago