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gregori [183]
3 years ago
5

100 POINTS!!! Which statement about rational numbers is correct?

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
6 0

Answer: Rational numbers have decimal expansions that repeat or terminate.

Step-by-step explanation:

The explanation of this is the non-terminating but repeating decimal expansion means that although the decimal representation has an infinite number of digits, there is a repetitive pattern to it. The rational number whose denominator is having a factor other than 2 or 5, will not have a terminating decimal number as the result.

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How do I solve for y in this equation? 2x+y=-9
Vesna [10]

Answer:

Step-by-step explanation:

y=-2x-9

subtract both sides by 2x

8 0
3 years ago
1. ABCD is a trapezoid with midsegment EF. If AB = 12 and CD = 24, what is the length of EF?
natali 33 [55]
For all of these answers, the equation used was (AB + CD)/2 = EF

1.12+24=36    36/2=18
2. 21 + 35 = 56    56/2 = 28
3. (7 + EF)/2 = 9 
    multiply by 2
   7 + EF = 18
   subtract 7
EF = 11

4. (AB + 32)/2 = 22
Multiply by 2
AB + 32 = 44
Subract 32
AB = 12

5. Average
3 0
4 years ago
Read 2 more answers
After 3 years what is the total amount of an investment of $1500 in an account paying 3.5% interest, compounded quarterly?
musickatia [10]
<span>$2,226.60 try to read it agian so easy for me

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3 0
4 years ago
Find the values of c such that the area of the region bounded by the parabola
KATRIN_1 [288]

<u>Solution-</u>

The two parabolas are,

y=16x^2-c^2 \ and \ y=c^2-16x^2

By solving the above two equations we calculate where the two parabolas meet,

So \ 16x^2-c^2 = c^2-16x^2 \Rightarrow 32x^2=2c^2 \Rightarrow x=\frac{1}{4}c

Given the symmetry, the area bounded by the two parabolas is twice the area bounded by either parabola with the x-axis.

\therefore Area=2\int_{-c}^{c}y.dx= 2\int_{-c}^{c}(16x^2-c^2).dx\\=2[\frac{16}{3}x^3-c^2x]_{-c}^{ \ c}=2[(\frac{16}{3}c^3-c^3)-(-\frac{16}{3}c^3+c^3)]=2[\frac{32}{3}c^3-2c^3]=2(\frac{26c^3}{3})\\=\frac{52c^3}{3}

So \frac{52c^3}{3}=\frac{250}{3}\Rightarrow c=\sqrt[3]{\frac{250}{52}}=1.68

5 0
4 years ago
14. Find mMK please :)
MrRissso [65]

Answer:

Step-by-step explanation:

11) strategy:  since they tell us. indirectly,  that the length of  JK is the same as LM then we can set those two equal, solve for X  and then.. when we have X we can figure out the lenght of JK  and LM and then just divide that by 2 go get PK  ( :0 Player Killer ???  no , not that PK)    

solve JK and LM

3x + 23 =9x-19

42 = 6x

7 = x

now that we know x = 7 plug it into either equation to come up with the length of JK or LM .  I'll pick JK just b/c it was 1st

3(7) + 23 = JK

21+23 = JK

44 = JK

now take half of 1/2*JK= 22  that is PK    ( are you sure that 's not player killer?)

PK = 22

12) strategy: set the two arcs BG and GC equal and solve for X, then plug x into either equation and the multiply the answer by 2 to find arc AB

9x-20 = 5x + 28

4x = 48

X = 12

9(12) -20 = BG

88 = BG

2*88 + AB

176 = AB

13) done

14)  strategy: find the angle at L,  and that will also be the arc of MK

<em>copy and past the below</em> helpful trig functions into your computer

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

<em>copy and past the above</em> :

use which ever trig function you want , we have all the sides of the triangle, I'll use CAH

Cos(Ф) = 9/15

Ф = arcCos(9/15)

Ф = 53.13010°

arc MK = 53.13010°

15)   strategy:  arc JK is just 2 times MK

2*MK = 106.26020°

arc MK = 106.26020°

16) find arc JPK   strategy:  JPK is just the remaining part of a full circle of 360 - MK  = 253.7397°

arc JPK = 253.7397°

7 0
3 years ago
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