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natima [27]
3 years ago
12

HELP ME PLZ!!!!!!!!       Find the solution of this system of equations.

Mathematics
1 answer:
Strike441 [17]3 years ago
7 0
Set equal to each other since both equal 90

5x-6y=-10x-6y
add 6y to both sides
5x=-10x
x=0


5(0)-6y=-90
-6y=90
divide by -6
y=-15

(x,y)
(0,-15)
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The following two triangles are similar find x
slavikrds [6]

Answer:

5

Step-by-step explanation:

As we can see they are similar triangles then

the ratio of the corresponding sides are equal then

x /25 = 9/45

x = 25 * 1/ 5

x = 5

Hope it will help :)

5 0
3 years ago
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The producer of the news station posted an article about the high school's football championship ceremoney on a new website. The
-Dominant- [34]
Let x be the number of hours and Let y be the number of views.

x              y
1             125 
2              250
3               375
4            500
5            625
3 0
3 years ago
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PLS PLS I NEED HELP I HAVE NO TIME I'LL MARK YOU BRAINLIST !!!
Dominik [7]

Answer:

1) y = 5/2x - 3/2

2) y = 2/5x - 4/5

Step-by-step explanation:

1)

(1, 1) and (3, 6)

m = (y2 - y1)/(x2 - x1)

m= (6 - 1)/(3-1)

m= 5/2

m= 5/2

y - y1 = m(x - x1)

y - 1 = 5/2(x - 1)

y - 1 = 5/2x - 5/2

y = 5/2x - 3/2

2)

(2, 0) and (7, 2)

m = (y2 - y1)/(x2 - x1)

m= (2 - 0)/(7 - 2)

m = 2/5

y - y1 = m(x - x1)

y - 0 = 2/5(x - 2)

y = 2/5x - 4/5

5 0
2 years ago
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A new phone system was installed last year to help reduce the expense of personal calls that were being made by employees. Befor
Leya [2.2K]

Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 700, \sigma = 50.

The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:

X = 790:

Z = \frac{X - \mu}{\sigma}

Z = \frac{790 - 700}{50}

Z = 1.8

Z = 1.8 has a p-value of 0.9641.

X = 575:

Z = \frac{X - \mu}{\sigma}

Z = \frac{575 - 700}{50}

Z = -2.5

Z = -2.5 has a p-value of 0.0062.

0.9641 - 0.0062 = 0.9579.

0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
1 year ago
Math homework help please
OLEGan [10]
16
divide 12 by 3 since its 3/4 of the whole thing so 1/4=4
3 0
3 years ago
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