This can be solve by using the formula
D = P( 1 – i)^n
Where d is the depreciation value after n years
P is the initial value
i is the depreciation rate
n is the years
D = 1/3 ( 1800)
D = 600
So
600 = 1800 ( 1- 0.45)^n
Solve for n
<span>N = 1.83 years</span>
Answer:
Step-by-step explanation:
<u>Exponential Growth
</u>
The natural growth of some magnitudes can be modeled by the equation:
Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.
The initial number of bacteria is Po=40 and it doubles (P=2Po) at t=20 min. With that point we can find the value of r:
Simplifying:
Solving for 1+r:
![1+r=\sqrt[20]{2}](https://tex.z-dn.net/?f=1%2Br%3D%5Csqrt%5B20%5D%7B2%7D)
The exponential function that models the situation is:
Answer:
-26
Step-by-step explanation:
- -32+3×2
- -32+6
- -26
By using BODMAS, any of the answers given is correct!
Answer:
t = (p - 1/2)/3
Step-by-step explanation:
p = 4t + 1/2 - t
combine like terms:
p = 3t + 1/2
subtract 1/2 from each side of the equation:
3t = p - 1/2
divide both sides by 3:
t = (p - 1/2)/3
Supplementary angles add up to 180º
If one is 40º, then the other is (180º-40º) = 140º
None of those choices describes a plane.
choice C is the only example of a plane.
