All categories

3 years ago

Solve each system of equations by graphing y=-1/2x+5 and y=3x-2

1 answer:

3 0

Just make the equations equal to each other. -0.5x+5=3x-2. Solve for x and find that it is 2, via simple algebra. Since you know x is 2, sub it in in either equation to find y. y should be 4. So the point that fits both equation is (2,4). This shows that the two graphs of these lines will intersect at this exact point.

If you were to graph these two lines, you ould see that the point of intersection is at (2,4) like we solved for.

You might be interested in

What is the solution to the equation 13.7y = 6.2y + 30?

il63 [147K]

Here, we are required to determine the solution to the equation: 13.7y = 6.2y + 30?

The solution to the equation is y = 7.5

The solution is thus,

13.7y = 6.2y + 30
13.7y - 6.2y = 30
7.5y = 30

Therefore, y = 30/7.5 = 4

Therefore, y = 4 is the solution to the equation.

Read more:

brainly.com/question/12184348

8 0

3 years ago

A cyclist rides his bike at a rate of 10 kilometers per hour. What is this rate in miles per hour. How many miles will the cycli

poizon [28]

Answer:

10 km/ hour = 6.25 miles/ hour

Step-by-step explanation:

cyclist travel in 5 hours = 6.25 x 5 = 31.25 miles

8 0

4 years ago

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

4 years ago

Which statement is true about judy's method?

aniked [119]

A. Judy made a mistake between Steps 1 and 2
To factor $x^{2} - 16$ , you have to factor it as $(x-2)(x+2)(x-4)$ , not $(x-2)(x+8)$ , because that will leave an extra 6x because of 8x - 2x.

3 0

4 years ago

Read 2 more answers

Find f(2) if f(x) = 2x + 1.<br> A) 3 <br> B) 5 <br> C) 7 <br> D) 9

Rufina [12.5K]

Answer:

The answer to your question is letter B

Step-by-step explanation:

Process

1.- Write the equation

f(x) = 2x + 1

find f(2)

2.- Substitute x for 2

f(2) = 2(2) + 1

3.- Simplify

f(2) = 4 + 1

f(2) = 5

5 0

3 years ago

Read 2 more answers