Which symbol makes the sentence true?

Circle A has a diameter of approximately 20 inches and an area of approximately 300 in2.

Katena32 [7]

Answer:

4. About 2,700 in2

Step-by-step explanation:

The area of a circle ( $A$ ), measured in square inches, is directly proportional to the square of its diameter ( $d$ ), measured in inches. That is:

$A \propto d^{2}$

$A = k\cdot d^{2}$

Where $k$ is the constant of proportionality, dimensionless.

In consequence, the following relationship between circles A and B is obtained:

$\frac{A_{B}}{A_{A}} = \frac{d_{B}^{2}}{d_{A}^{2}}$

The area of the circle B is now cleared:

$A_{B} =\left(\frac{d_{B}}{d_{A}} \right)^{2}\cdot A_{A}$

Given that $d_{A} = 20\,in$ , $d_{B} = 60\,in$ and $A_{A} = 300\,in^{2}$ , then:

$A_{B} = \left(\frac{60\,in}{20\,in} \right)^{2}\cdot (300\,in^{2})$

$A_{B} = 2700\,in^{2}$

Therefore, the correct answer is 4.

7 0

3 years ago

What is the slope of the line given by the following equation? Give an exact number. -13x 5y=-7

Black_prince [1.1K]

The slope should be 13/5x

8 0

3 years ago

How can you show your work on rounding

MAXImum [283]

U can show your work by underlining what your rounding and showing which place it is it the right of it but there is no mathematical work

6 0

3 years ago

Read 2 more answers

A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0

3 years ago

What is an equation of the line that passes through the points (8,2) and (7,1)?

gogolik [260]

Answer:

Step-by-step explanation:

first, we find the slope

slope = (y2 - y1) / (x2 - x1)

(8,2)....x1 = 8 and y1 = 2

(7,1)....x2 = 7 and y2 = 1

now we sub

slope = (1 - 2) / (7 - 8) = -1/-1 = 1

y = mx + b

slope(m) = 1

use either of ur points...I will use (8,2)...x = 8 and y = 2

now we sub and find b, the y intercept

2 = 1(8) + b

2 = 8 + b

2 - 8 = b

-6 = b

so ur equation is : y = 1x - 6....or just y = x - 6 <===

8 0

3 years ago