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enot [183]
3 years ago
6

a square with sides of length 5 is positioned inside a square with sides of length 7. What is the total area between the squares

? ​
Mathematics
2 answers:
Novosadov [1.4K]3 years ago
4 0
24 I believe because the biggest one is 49 and the second is 25 so subtract and it’s 24.
Vlad [161]3 years ago
3 0
5x7=35
your answer is 35 hope i helped
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Shaun collects coins. He has 18 quarters and 24 pennies in a jar. What is the ratio of quarters to pennies in a jar?
Nutka1998 [239]

Answer:

18:24 or simplest form is 3:4

Step-by-step explanation: If you don't need to simplify then it is 18:24, but if you simplify it by dividing 18 and 24 by 6, then the answer is 3:4 :)

5 0
3 years ago
Read 2 more answers
James drove 6 miles south and then 3 miles west.how far is he from his starting point
Minchanka [31]

Answer:

9 miles

Step-by-step explanation:

A 6+3 is nine

7 0
3 years ago
If p(x) = 3x – 2and n (x) = 2x – 5, what is the value of (n/p) (1)?
Liula [17]

Answer:

-3

Step-by-step explanation:

We want (n/p)(1).  We can obtain this by finding n(1) and p(1) and then dividing as indicated:

p(1) = 3(1) - 2 = 1

n(1) = 2(1) - 5 = -3

Then   (n/p) (1) = -3/1, or just -3

5 0
2 years ago
I don't want the answer, but I want to know how you got that answer.
anastassius [24]

Answer:

n = 5

Step-by-step explanation:

4n+5n+15=5n+7n\\\\9n+15=12n\\\\9n+15-15=12n-15\\\\-3n=-15\\\\\frac{-3n=-15}{-3}\\\\ \boxed{n=5}

Hope this helps.

8 0
3 years ago
A triangle has vertices at (1,10), (-5,2), and (7,2). What is its orthocenter. Show your work.
kondor19780726 [428]

Answer:

Question: What is the orthocenter of a triangle with the vertices (-1,2) (5,2) and (2,1)?

The coordinates of point A are (-1,2), point B are (5,2), and point C are (2,1).

The orthocent is the intersection of the three altitudes. An altitude goes from a vertex and is perpendicular to the line containing the opposite side.

In the coordinate plane the equations of the altitudes can be found and then a system of equations can be solved.

Altitude 1. From point C perpendicular to the line containing side AB.

Slope of line AB is 0 (horizontal line), a vertical line is perpendicular to a horizontal line. Thus, the equation of altitude 1 is  x=2 .

Altitude 2. From point B perpendicular to the line containing side AC.

Slope of line AC is  −13 , the slope of a line perpendicular to line AC is 3. The equation of altitude 2 is  y=3x−13  

Altitude 3. From point A perpendicular to the line containing side BC.

Slope of line BC is  13 , the slope of a line perpendicular to line BC is  −3 . The equation of altitude 3 is  y=−3x−1  

The orthocenter is the point where all three altitudes intersect.

x=2  

y=3x−13  

y=−3x−1  

Use substitution to solve the first two equations  y=3(2)−13=−7  

The orthocenter is the point  (2,−7)  

we did not need the third equation, but we can use it as a check, plug the coordinates into the third equation:

−7=−3(2)−1  

−7=−6−1  

−7=−7  it works.

3 0
3 years ago
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