Can someone please help me out I’m so lost !!!!!!!
2 answers:
Hello!
Let's quickly review our trigonometric ratios.
Sin= Opposite/Hypotenuse
Cos= Adjacent/Hypotenuse
Tan= Opposite/ Adjacent
Let's find these for angle G.
Opposite:15
Adjacent: 8
Hypotenuse: 17
First of all, we have sin G= 8/15. The adjacent side is 8, which is not the opposite or hypotenuse, so A is incorrect.
We have cos G= 8/15. That is the adjacent divided by the opposite, not adjacent over hypotenuse, so B is incorrect.
Finally, we have sin G= 15/17. This is the opposite divided by the hypotenuse, so it is correct.
Therefore, our answer is .
I hope this helps!
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a. Find the graph of their common region in the attachment
b. The area of the common region of the graphs is 8 units²
<h3>a. How to sketch the region common to the graphs?</h3>Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.
- The graph of x ≥ 2 is the region right of the line x = 2.
- The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
- To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.
So, the graph of x + y ≤ 6 is the region below the line y = - x + 6
From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)
Find the graph of their common region in the attachment
<h3>b. The area of the common region</h3>From the graph, we see that the common region is a right angled triangle with
- height = 4 units and
- base = 4 units
So, its area = 1/2 × height × base
= 1/2 × 4 units × 4 units
= 1/2 × 16 units²
= 8 units²
So, the area of the common region of the graphs is 8 units²
Learn more about region common to graphs here:
#SPJ1
The data is missing in the question. The data is provided below :
Document : 1 2 3 4 5 6 7 8
Brand A 17 29 18 14 21 25 22 29
Brand B 21 38 15 19 22 30 31 37
Solution :
State of the hypothesis of the null hypothesis and alternate hypothesis.
Null hypothesis :
Alternate hypothesis :
These hypothesis is a one tailed test. The null hypothesis will get rejected when the mean difference between the sample means is very small.
Significance level = 0.05
Therefore the standard error is :
= 3.602
And the degree of freedom, DF = 14
= -1.319
Here, = standard deviation of the sample 1
= standard deviation of the sample 2
= size of the sample 1
= size of the sample 2
= mean of the sample 1
= mean of the sample 2
d = the hypothesis difference between the population mean
The observed difference in a sample means t static of -1.32. From t distribution calculator to determine P() = 0.1042
Since the P value of 0.1042 is greater than significance level o 0.05, we therefore cannot reject the null hypothesis.
But from the test, we have no sufficient evidence that supports that Brand A is better than Brand B.