Answer:
CD = 24
Step-by-step explanation:
If G is the centroid, then CG = GD. (12 = 12)
Since CD is CG and GD combined, we would just add these two numbers to find the total length of CD.
CG + GD = CD
12 + 12 = 24
Answer:

Step-by-step explanation:
We are given the following in the question:
The numbers of teams remaining in each round follows a geometric sequence.
Let a be the first the of the geometric sequence and r be the common ration.
The
term of geometric sequence is given by:


Dividing the two equations, we get,

the first term can be calculated as:

Thus, the required geometric sequence is

Answer:
zeros are 4 and 3
Step-by-step explanation:
2x - 6 =0
x -4 = 0
solve both of these for x
these are your zeros
Answer:
-3
Step-by-step explanation: