Please help me out !! ( I will mark brainliest)

Mathematics

1 answer:

lisov135 [29]2 years ago

3 0

Question 1: The y-intercept is where the line crosses the y-axis. The increments of the y-axis is by 20, and the y-intercept is at (0, 20).

The slope is the change in y over the change in x. Find two points:

(0, 20) and (2, 80)

Now:

(80 - 20)/(2 - 0) = 60/2 = 30

Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

So:

y = 30x + 20

Question 2: Again, look for the y-intercept, which is pretty clear. It's (0, 60).

Now find two points:

(0, 60) and (2, 40)

Find the slope:

(40 - 60)/(2 - 0) = -20/2 = -10

So, the equation is:

y = -10x + 60

And, there you go!

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Please answer this question now

Alex787 [66]

Answer:

541.7 (m2)

Step-by-step explanation:

Applying the sine theorem:

WV/sin(X) = XV/sin(W)

=> WV = XV*sin(X)/sin(W) = 37*sin(50)/sin(63) = 31.81

Angle V = 180 - X - W = 180 - 50 - 63 = 67

Denote WH is a height of the triangle VWX, H lies on XV

=> WH = WV*sin(V) = 31.81*sin(67) = 29.28

=> Area of triangle VWX is calculated by:

S = side*height/2 = XV*WH/2 = 37*29.28/2 = 541.7 (m2)

8 0

2 years ago

Find the perimeter use pi

balandron [24]

Since d x pi = circumference
I use 3.14 as pie

I did 9 x pi = 28.26 I DID NOT divide this by two because there are three half circles and 28.26 counts as two of them

Since there is another half circle I divide 28.26 by 2

28.26 + 14.13 = 42.39

Now plus the bottom length

42.39 + 9 = 51.39

Brainliest answer please?

8 0

3 years ago

How do you do this question?

mihalych1998 [28]

Answer:

C) π/6

Step-by-step explanation:

The area under the curve from x=-π/2 to x=k is 3 times the area under the curve from x=k to x=π/2.

$\int\limits^k_{-\frac{\pi }{2}} {cos\ x} \, dx = 3\int\limits^{\frac{\pi }{2}}_k {cos\ x} \, dx\\sin\ x\ |^{k}_{-\frac{\pi }{2}} = 3\ sin\ x\ |^{\frac{\pi }{2}}_k\\(sin\ k - (-1)) = 3\ (1 - sin\ k)\\sin\ k + 1 = 3 - 3\ sin\ k\\4\ sin\ k = 2\\sin\ k = \frac{1}{2}\\k = \frac{\pi}{6}$