The answer is C. I solved for the first variable in one of the equations then substitute the result into the other equation.
C=2 times j
c=2j
o=j-6
c+j+o=58
subsitte j-6 for o and 2j for c
2j+j+j-6=58
4j-6=58
add 6 to both sides
4j=64
divide both sides by 4
j=16
sub back
c=2j
c=2(16)
c=32
o=j-6
o=16-6
o=10
curtis=32
olivia=10
jonathan=16
equations are
c+j+o=58
c=2j
o=j-6
Answer:
35y2+13y−12
=35y2+28y−15y−12
=7y(5y+4)−3(5y+4)
=(7y−3)(5y+4)
Therefore, the possible length and breadth are 7y-3 units and 5y+4 units
Answer:
a
Step-by-step explanation:
Answer:
The multiplicative inverse of 1/2 is 2.