Differentiate:x^2 + y^2 = 4
You get this:2x + 2yy' = 0
bring the x variable on the other side:2yy' = -2x
Now divide 2y to leave y' by itself:y' = -2x/2y
Answer: y' = -x/y
The given relation is not a implicit solution to the given differential equation.
Pythagoras theorem:
hypotenuse²=leg₁²+leg₂²
Data:
leg₁=8
leg₂=15
hypotenuse=s
hypotenuse²=(8)²+(15)²
hypotenuse²=64+225
hypotenuse²=289
hypotenuse=√289
hypotenuse=17
Answer: s=17
Something u need to do dude
You answer is the third option
